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Description

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2.

Note:

  1. The length of both num1 and num2 is < 110.

  2. Both num1 and num2 contains only digits 0-9.

  3. Both num1 and num2 does not contain any leading zero.

  4. You must not use any built-in BigInteger library or convert the inputs to integer directly.

Tags: Math, String

思路

题意是让你计算两个非负字符串的乘积,我们模拟小学数学的方式来做,一位一位模拟计算,再各位累加。

class Solution {
    public String multiply(String num1, String num2) {
        if (num1.equals("0") || num2.equals("0")) return "0";
        int l1 = num1.length(), l2 = num2.length(), l = l1 + l2;
        char[] ans = new char[l];
        char[] c1 = num1.toCharArray();
        char[] c2 = num2.toCharArray();
        for (int i = l1 - 1; i >= 0; --i) {
            int c = c1[i] - '0';
            for (int j = l2 - 1; j >= 0; --j) {
                ans[i + j + 1] +=  c * (c2[j] - '0');
            }
        }
        for (int i = l - 1; i > 0; ++i) {
            if (ans[i] > 9) {
                ans[i - 1] += ans[i] / 10;
                ans[i] %= 10;        
            }
         }
        StringBuilder sb = new StringBuilder();
        int i = 0;
        for (; ; ++i) if (ans[i] != 0) break;
        for (; i < ans.length; ++i) sb.append((char) (ans[i] + '0'));
        return sb.toString();
    }
}

结语

如果你同我们一样热爱数据结构、算法、LeetCode,可以关注我们 GitHub 上的 LeetCode 题解:LeetCode-Solution