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[BUG] $playTrack[a url;url] does not add to queue #17
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can u send minimal code that will cause this |
Sorry I rechecked my code and apparently this behavior occurs because my play command always had $joinVc then starts a $playTrack |
Sorry for the inconvenience, but can we maybe change how $joinVc behaves when the bot is already in the current VC so it doesn't kill the current song/queue? |
we have $hasPlayer for this that gives bot already in vc or not u can use with old $if |
$hasPlayer returns true even if the bot was disconnected out of the VC though. (unless disconnected through $leaveVC) |
Another issue I have encountered with $playTrack is that when you try to play a song via a yt url it doesn't play, only text works |
the Yt link needs to be of type: https://youtube.com/watch?v=id
…On Mon, 27 May, 2024, 3:39 am Mody-0, ***@***.***> wrote:
Another issue I have encountered with $playTrack is that when you try to
play a song via a yt url it doesn't play, only text works
$playTrack[ayturl;youtube] won't work
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how do you get that type specifically cause the one I got from the share video thing was like https://youtu.be/pZcP-fCwoao?si=WXXHqoD5H6sF9DxK |
Just split by the |
Current Behavior
When you play a song via $playTrack[the url;url] you cannot add another song to the queue, using the function again to add to queue will just play another song and skip the current and never add any songs to queue.
Expected Behavior
Using the function while a song is playing should add the second song to queue
Steps To Reproduce
1- Play a song using the url field on $playTrack (I used a url that isn't related to youtube, Spotify.. or any other platform)
2- Try adding another song via the same url field on $playTrack
3- Bot will skip the current song and start playing the song added in step two.
Environment
Anything else?
No response
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