How to call a PHP function with dynamic generated function name?

[PetersOtto]

Hello everyone!
I have a question for the php specialists 😀

I have a variable that is filled dynamically. This variable contains the function name. How can I call the function?
I thought of call_user_func(). Unfortunately the function will not found. I think it is due to the missing $this->.

I am looking for something like this but in the right: 😬

$choosedFilter = "sharpen";
$image = $this->$choosedFilter($image);

Does anyone have an idea?

[PetersOtto]

Oh, I think I've found the answer myself.

https://www.php.net/manual/en/functions.variable-functions.php

Have a nice weekend!

[GiovanniSalmeri]

Also

call_user_func(array($this, $choosedFilter), $image);

should do the trick.

[PetersOtto]

It do! Thank you 😀