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Running scasa from a symlink is not possible as Scasa expects to be able to access the scasa directory via the "which scasa" command (see SCASA_WRAP_V1.0.0.pl line 36), however, no error message is provided. It is my understanding that using "readlink -f" on the output of the "which scasa" command will return the appropriate directory even if the which scasa command returns the location of the symlink. See https://unix.stackexchange.com/questions/22128/how-to-get-full-path-of-original-file-of-a-soft-symbolic-link
This error is not obvious to the user; Scasa simply "finishes" running without generating an index or count matrix.
The text was updated successfully, but these errors were encountered:
Running scasa from a symlink is not possible as Scasa expects to be able to access the scasa directory via the "which scasa" command (see SCASA_WRAP_V1.0.0.pl line 36), however, no error message is provided. It is my understanding that using "readlink -f" on the output of the "which scasa" command will return the appropriate directory even if the which scasa command returns the location of the symlink. See https://unix.stackexchange.com/questions/22128/how-to-get-full-path-of-original-file-of-a-soft-symbolic-link
This error is not obvious to the user; Scasa simply "finishes" running without generating an index or count matrix.
The text was updated successfully, but these errors were encountered: