Docs of functions: is this really a closure?

[waleed-alfaifi]

Hey everyone,

I was reading the docs of functions in JavaScript and I ran into this example:

function addSquares(a, b) {
  function square(x) {
    return x * x;
  }
  return square(a) + square(b);
}
a = addSquares(2, 3); // returns 13
b = addSquares(3, 4); // returns 25
c = addSquares(4, 5); // returns 41

The docs say that the inner function square forms a closure with its enclosing function addSquares.

Since the inner function forms a closure, you can call the outer function and specify arguments for both the outer and inner function.

As far as I know, closures are created only if the nested function is referencing variables of the outer function. However, in the above example, square is not referencing any variables/functions of addSquares and it's just sitting there in the context of addSquares.

I was going to open a PR for this, but I wanted to make sure I understand it well.

[ghost]

You should be correct - neither of these functions enclose anything from an outer scope.
It is correct in that you could call the outer function from it, but as it does not reference the function within the body, it does not close over it.

[shashiranjan999]

you are correct according to the browser devtool till now we are not accessing any variable from outer scope it will not form closure

attach image from reference if i am wrong please correct me.you can see in image inner function not create closure with outer function

[Shubham962546]

Great finding bro have faced same issue . should be rectified